Given a binary tree, determine if it is height-balanced.
For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the two subtrees of every node never differ by more than 1.
解题思路:
递归.
int depth(TreeNode * root){
if(root == NULL) return 0;
return std::max(depth(root->left),depth(root->right))+1;
}
bool isBalanced(TreeNode *root)
{
if(root == NULL) return true;
int left = depth(root->left);
int right = depth(root->right);
if (abs(left - right) > 1) return false;
return isBalanced(root->left) && isBalanced(root->right);
}
其实递归过程中好多都算重复了。 可以将判断过程融合在算高度的方法里。
int depth(TreeNode * root){
if(root == NULL) return 0;
int left = depth(root->left);
int right = depth(root->right);
if(left == -1 || right == -1 || abs(left-right) > 1)
return -1;
return std::max(left, right)+1;
}
bool isBalanced(TreeNode *root)
{
if(root == NULL) return true;
return depth(root) >= 0;
}