3Sum Closest 题解
题目来源:3Sum Closest
> Given an array S of n integers, find three integers in S such that the sum is closest to a given number, target. Return the sum of the three integers. You may assume that each input would have exactly one solution. For example, given array S = {-1 2 1 -4}, and target = 1. The sum that is closest to the target is 2. (-1 + 2 + 1 = 2).
解题思路:
跟3-sum思路一致。
int threeSumClosest(vector<int> &num, int target)
{
int n = num.size();
int result = 0;
int closest = INT_MAX;
std::sort(num.begin(), num.end());
for(int i = 0; i < n-2; i++)
{
if (i > 0 && num[i-1] == num[i]) continue;
int begin = i+1;
int end = n - 1;
while(begin < end)
{
int sum = num[i] + num[begin] + num[end];
if(closest > abs(sum-target))
result = sum, closest = abs(sum-target);
if(sum > target)
--end;
else if (sum < target)
++begin;
else
return sum;
}
}
return move(result);
}
Last updated
Was this helpful?